Question

The present age of Raju's father is twice that of Raju. After 6 years, the sum of their
ages would be 87 years. Find their present ages.​

Answer 1

Answer:

Let the age of son be x.

Thus, age of father is 4x.

After 5 years, their ages will be x+5 and 4x+5 years respectively.

As per the question, we have

4x+5=3(x+5)

⇒4x+5=3x+15

⇒x=10

Age of father will be 4x=4×10=40 years.

Thus when son is 10 years old, father is 40 years.

Answer 2

Answer :-

• The present age of Raju is 25 years.
• The present age of Raju's father is 50 years.

Given :-

• The present age of Raju's father is twice that of Raju.

• After 6 years, the sum of their ages would be 87 years.

To find :-

• Their present ages.

Step-by-step explanation :-

• Here, we have to find the present ages of Raju and his father.

Let the age of Raju be "x".

As his father's age is twice his age, therefore his age will be "2x".

After 6 years,

• Raju's age will be "x + 6".
• His father's age will be "2x + 6".

It has been given that :-

• After 6 years, the sum of their ages would be 87 years.

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Therefore,

$\hookrightarrow\sf x + 6 + 2x + 6 = 87$

Adding the variable terms,

$\hookrightarrow\sf3x + 6 + 6 = 87$

Adding the constant terms,

$\hookrightarrow\sf3x + 12 = 87$

Transposing 12 from LHS to RHS, changing it's sign,

$\hookrightarrow\sf3x = 87 - 12$

Subtracting 12 from 87,

$\hookrightarrow\sf3x = 75$

Transposing 3 from LHS to RHS, changing it's sign,

$\hookrightarrow\sf x = \dfrac{75}{3}$

Dividing 75 by 3,

$\hookrightarrow\underline{ \boxed{ \sf x = 25}}$

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Hence, their present ages are :-

$\leadsto\bf x = 25 \: years.$

$\leadsto\bf2x = 2 \times 25 = 50 \: years.$

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