Math, asked by IronMan1000, 8 months ago

The present age of rohan and divya are in the ratio 4:3.Six years hence,their ages will be in the ratio 6:5.find there present age.

Answers

Answered by anshugang
23

Answer:

Step-by-step explanation:

Age of Rohan after 6 years = 4x + 6 .

Age of Divya after 6 years = 3x + 6.

Ratio of their ages = 4x + 6: 3x + 6 .

But,it is given 6:5.

So, According to question ,

4x+ 6 : 3x + 6 = 6: 5

or 4x + 6/ 3x + 6 = 6 /5.

or 5( 4x + 6 ) = 6(3x + 6).

or 20x + 30 = 18x + 36.

or 20x - 18x = 36 - 30.

or 2x = 6.

Therefore x = 3 .

So, present age of Rohan = 4x = 4× 3 = 12 yrs.

Present age of Divya = 3x = 3 × 3 = 9yrs.

Answered by Harshit2445
7

Answer:

Let the present age of Rohan be 4x then of Divya is 3x and according to question

4x+6/3x+6=6/5

→20x+30=18x+36

→2x=6

→x=3

Hence their present ages are 12 and 9 respectively...

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