Math, asked by AMIT111111110, 1 year ago

THE PRESENT AGE OF SAHIL MOTHER IS THREE TIMES THE PRESENT AGE OF SAHIL. AFTER 5 YEARS THEIR AGES WILL ADD TO 66 YEARS. FIND THEIR PRESENT AGES

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Answered by preethi25
536
let the present age of Sahil be x,sahil's mother age be 3x.5years later sahil's age is x+5,sahil's mother's age is 3x+5.sum if their ages after 5years is 4x+10.

4x+10=66
4x=66-10
x=56÷4
x=14.
sahil's present age is 14& sahil's mothers age is 3×14=42 years.
after 5 years
sahil's age is 14+5=19
sahil's mother age is 42+5=47
19+42=66years

preethi25: mark me as brainliest
Answered by syed2020ashaels
6

Let the present age of Sahil = y years

Let the present age of Sahil's mother= x years.

Given that present age of Sahil's mother is three times the present age of Sahil

x = 3y

After five years Sahil's age will be

y + 5

After five years Sahil's mother age will be

x + 5 \\  = 3y + 5

Now, it is given that after 5 years the sum of their ages will be 66.

y + 5 + 3y + 5 = 66 \\ 4y + 10 = 66 \\ 4y = 66 - 10 \\ 4y = 56 \\ y = 56 \div 4 \\ y = 14

Sahil's age

y = 14 \: years

Sahil's mother age is

x = 3y \\  = 3 \times 14 \\  = 42 \: years

Therefore, present ages of Sahil and Sahil's mother are 14 years and 42 years

# SPJ2

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