The present age of Sahil's mother is 3 times the present age of Sahil. After 5 years their ages will added to 66 years find the present age of Sahil.
Answers
Answered by
14
Let the present age of Sahil be 'x'.
Then, present age of Sahil's mother is '3x'
After 5 years, age of Sahil = x+5
Age of Sahil's mother = 3x+5
Sum of their ages after 5 years = 66
Therefore,
(x+5)+(3x+5)=66
4x+10=66
4x=66-10
4x=56
x=56/4
x=14
Therefore, present age of Sahil is 14 years
Then, present age of Sahil's mother is '3x'
After 5 years, age of Sahil = x+5
Age of Sahil's mother = 3x+5
Sum of their ages after 5 years = 66
Therefore,
(x+5)+(3x+5)=66
4x+10=66
4x=66-10
4x=56
x=56/4
x=14
Therefore, present age of Sahil is 14 years
Answered by
4
let the present age of sahil be =x
then the age of sahil mother =3x
after five years sahil age =x+5
after five is sahils mother age =3x+5
sum of their age after five years= 66
therefore
[x+5] +[3x+5]=66
4x +10=66
4x =66-10
4x =56
x=56/4
x =14
the present age of sahil is 19
then the age of sahil mother =3x
after five years sahil age =x+5
after five is sahils mother age =3x+5
sum of their age after five years= 66
therefore
[x+5] +[3x+5]=66
4x +10=66
4x =66-10
4x =56
x=56/4
x =14
the present age of sahil is 19
Similar questions