Question

The present age of Sahil's mother is 3 times the present age of Sahil. After 5 years their ages will add to 66 years. Find their present ages.​

Answer 1

Answer:

Aage of Sahil=14 years

Age of his mother=42 years

Step-by-step explanation:

Let the age of Sahil be x years

Let the age of his mother be y years

According to first condition,

3x=y

3x-y=0 ..........(i)

According to second condition,

(x+5)+(y+5)=66

x+y+10=66

x+y=66-10

x+y=56.........(ii)

Adding equation (i) and (ii)

4x=56

x=56/4

x=14 years

Putting x=14 in equation (ii)

14+y=56

y=56-14

y=42

So age of Sahil is 14 years and his mother's age is 42 years

Answer 2

$\large{\underline{\underline{\red{\tt{Given:- }}}}}$

• Present age of Sahil's mother is 3times the present age of Sahil.
• After 5 years their ages will be add to 66 years.

$\large{\underline{\underline{\red{\tt{To\:Find:- }}}}}$

• Their present ages.

$\large{\underline{\underline{\red{\tt{ Answer:-}}}}}$

Given that present age of Sahil's mother is three times the present age of side and after 5 years their ages will add to 266 years.

Let the present age of Sahil be x then the age of size mother is equal to 3x.

After five years :-

• Age of Sahil is equal to + 5.
• Age of science mother is equal to 3x + 5.

Now it is given that the sum of age of Sahil and his mother is equal to 66 years.

⇒ (3x + 5) + (x + 5) = 66 .

⇒ 3x + 5 + x + 5 = 66.

⇒ 4x + 10 = 66.

⇒ 4x = 66-10.

⇒ 4x = 56.

⇒ x = 56/4.

⇒ x = 14 .

Hence we got the value of x as 14 .

So , the the present ages of,

• Sahil = x yrs = 14 yrs .
• Sahil's mother = 3x yrs. = 14×3 yrs = 42yrs.