Question

The present age of sahil's mother is three times the present age of Sahil. After 5 years their ages will add at 66 years . Find their present ages .

Answer 1

$\huge\red{Answer}$

Let ,

The Present Age Of Sahil's Mother Be x ,

The Present Age Of Sahil Be y ,

From eqn 1 ,

x = 3y

x - 3y = 0

From eqn 2 ,

( x + 5 ) + ( y + 5 ) = 66

x + y + 10 = 66

x + y = 56

Substract Eqn 1 From Eqn 2 ,

x + y = 56

- x - 3y = 0

4y = 56

y = 56 ÷ 4

y = 14

Put y = 14 in Eqn 2 ,

x + y = 56

x + 14 = 56

x = 56 - 14

x = 42

So, The Age Of Sahil's Mother Is 42 Years And Age Of Sahil Is 14 Years .

Answer 2

Answer:

$\large\sf{present \: age \: of \: sahil = 14years}$

Step-by-step explanation:

$\large\sf{lets \: present \: age \: of \: sahil \: be : \: x}$

$\large \sf{present \: age \: of \: sahil's \: mother \: be : 3x}$

After 5 years,

$\large\sf{age \: of \: sahil \: = \: (x + 5) \: years}$

$\large \sf{age \: of \: sahil's \: mother \: = (3x + 5) \: years}$

$\sf{➡( x + 5) + (3x + 5) = 66 } \\ \\\sf{ ➡x + 3x + 5 + 5 = 66} \\ \\\sf{ ➡4x + 10 = 66} \\ \\\sf{ ➡4x = 66 - 10} \\ \\\sf{ ➡4x = 56 } \\ \\ \sf{➡x = \frac{56}{4}} \\ \\ \green{ \sf{➡x = 14}}$

Now,

• Present age of sahil = 14 years.
• Present age of sahil's mother = 3x = 3×14 = 42.