Question

the present age of Sahil,s mother is three times the present age of Sahil. after 5 years their ages will add to 66 years . find their present ages​

Answer 1

$\large\mathfrak \pink{Solution:-}$

$\underline \mathbb{GIVEN:-}$

➙The present age of Sahil,s mother is three times the present age of Sahil.

➙After 5 years their ages will add to 66 years.

$\underline \mathbb{TO \: FIND:-}$

➙Their present ages.

$\underline \mathbb{ASSUMPTION:-}$

➙Let, the present age of Sahil be x

➙And the present age of Sahil's Mother be 3x

➙After 5 years :-

➙Sahil's age will be x+5

➙Sahil's Mother age will be 3x+5

➙Their total age will be 66 years after 5 years.

$\underline \mathbb{BY \: THE \: PROBLEM:-}$

$x + 5 + 3x + 5 = 66 \\ \\ \implies \: 4x + 10 = 66\\ \\ \implies \: 4x = 66 - 10\\ \\ \implies \: 4x = 56\\ \\ \implies \: x = \frac{56}{4} \\ \\ \implies \: x = 14$

$\underline \mathbb{ANSWER:-}$

➙The present age of Sahil = x = 14 years.

➙The present age of Sahil's Mother = 3x = 14×3 = 42 years.

Answer 2

Let the present age of Sahil be x years.

Given that,

The present age of Sahil's mother is three times of Sahil

Sahil's mother = 3x years

• According to the question,

After 5 years Sahil and his mother's age will be 66 when added.

So,

After 5 years,

• Sahils age = (x + 5) years
• Sahil's mother age = (3x + 5) years

Now,

⇒ (x+5) + (3x+5) = 66

⇒  x + 5 + 3x + 5 = 66

⇒ 4x + 10 = 66

⇒ 4x + 66 - 10

[By transporting 10  to RHS]

⇒ 4x = 56

⇒ x = 56 ÷ 4

[By transporting 4 to RHS]

⇒ x = 14

Therefore,

The present age of Sahil is = x years = 14 years

And the present age of Sahil's mother is = 3x years = (3 * 14) = 42 years