Math, asked by bhoiabhishek605, 10 months ago

the present age of sahils mother is 3times the present age of sahil after 5 years their age will add to 66 year find their present age​

Answers

Answered by ankitphanzira
1

Answer:

Step-by-step explanation:

let the present age of Sahil be x,sahil's mother age be 3x.5years later sahil's age is x+5,sahil's mother's age is 3x+5.sum if their ages after 5years is 4x+10.

4x+10=66

4x=66-10

x=56÷4

x=14.

sahil's presentage is 14& sahil's mothers age is 3×14=42 years.

after 5 years

sahil's age is 14+5=19

sahil's mother age is 42+5=47

19+42=66years

Answered by dhirajmdhande200529
2

Answer:

Sahils age- 14 years

Sahils mother's age = 42 years

Step-by-step explanation:

let sahils age be x and sahils mother's age be y.

sahils age= x

By the first condition:-

Sahils mother's age= 3x.

After 5 yers:-

Sahils age= x+ 5

Sahils mother's age = 3x+ 5

By the second condition:-

x+5 + 3x + 5= 66

4x+ 10 = 66

4x= 66- 10

4x= 56

x= 56/4

x= 14

Now,

Sahils age= x = 14 years

Sahils mother's age = 3x = 3 (14) = 42 years

Therefore, Sahils present age is 14 years and the present age of his mother is 42 years

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