Math, asked by rekhadevi28gmailcom, 10 months ago

the present age of Savitri is equal to the square of present age of his daughter 1 year ago the age of Savitri was 8 times the age of a Daughter find the age of a daughter​

Answers

Answered by tejurosh
0

SAVITRI BE X YRS

DAUGHTER BE D YRS

S =D^2

S-1 = 8(D-1)

D^2-1 = 8D -8

D^2 - 8D + 7 =0

D^2-7D-D+7=0

D(D-7)-1(D-7)=0

(D-7)(D-1)=0

D=7,1

IF D =7

S= 49

IF D=1 S= 1

DAUGHTER AND SAVITRI CANNOT BE OF SAME AGE

HENCE DAUGHTER IS 7 YRS AND SAVITRI IS 49 YRS

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