Question

The present age of shail mother is three times the present age of shail after 5 years their ages will be added to 58 find the present age

Answer 1

shail's mother =36 yrs

shail=12yrs

Answer 2

Appropriate Question:

The present age of Shail's mother is three times the present age of Shail. After 5 years, their ages will add up to 58. Find their present age.

Answer:

★ $\fbox\pink{\sf Present\:age\:of\:Shail\:is\:12\:years.}$

★ $\fbox\pink{\sf Present\:age\:of\:Shail's\:mother\:is\:36\:years.}$

Step-by-step explanation:

$\mapsto\large\underline\mathfrak\green{Letting\:their\:age:-}$

• Shail's age = x
• Shail's mother's age = 3x

$\mapsto\large\underline\mathfrak\green{After\:5\:years:-}$

• Shail's age = (x + 5)
• Shail's mother's age = (3x + 5)

$\leadsto\large\underline\mathfrak\pink{Equation:-}$

:$\implies\textsf{(x+5)+(3x+5)=58}$

:$\implies\textsf{x+5+3x+5 = 58}$

:$\implies\textsf{4x+10 = 58}$

:$\implies\textsf{4x = 58-10}$

:$\implies\textsf{4x = 48}$

:$\implies\sf{x = \cancel{\dfrac{48}{4}} = 12}$

:$\implies\fbox\green{\sf x = 12}$

$\mapsto\large\underline\mathfrak\green{Putting\:the\:value:-}$

• Shail's age = x = 12 years
• Shail's mother's age = 3x = 3(12) = 36 years

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