The present age of Sita's father is 3 times the present age of Sita. After 6 years, sum of their ages will be 68. Find their present ages.
Answers
Given :-
• Present age of Sita's father is three times the present age of Sita.
• After six years, sum of their ages will be 68.
To Find :-
• Their present ages.
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Let present age of Sita be x
Present age of Sita's father will be 3x
After six years, Sita's age will be 6 + x
After six years, Sita's father age will be 6 + 3x
According to question :-
• After six years, sum of their ages will be 68
Then,
(6 + x) + (6 + 3x) = 68
=> 6 + x + 6 + 3x = 68
=> 12 + 4x = 68
=> 4x = 68 - 12
=> 4x = 56
=> x = 56/4
=> x = 14
=> 3x = 3 × 14 = 42
Hence, present ages of Sita and her father are 14 and 42 years respectively.
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AnswEr:-
Your Answer Is,
- Sita's age = 14 Years.
- Sita's father age = 42 years.
ExplanaTion:-
Given:-
- Sita's father's age is 3 times the age of Sita.
- After 6 years sum of their ages would be 68.
To Find:-
- Their present ages.
Now,
- Let the present age of Sita be 'x'
- And hence her father's present age = '3x'
So,
- Age of Sita after 6 years = (x + 6 years)
- Age of her father after 6 years = (3x + 6 years).
Therefore ATQ:-
↦ (x + 6 years) + (3x + 6 years) = 68 years.
↦ x + 6 years + 3x + 6 years = 68 years.
↦ 4x + 12 years = 68 years.
↦ 4x = (68 - 12) years.
↦ 4x = 56 years.
↦ x = 56 years/4.
↦ x = 14 years.
So her Father's age,
= 3x
= 3 × 14 years
= 42 years.