Math, asked by fumansingh780, 10 months ago

The present age of son is five years and his father age is 28 years in how many years will the father's age will be twice the age of his son

Answers

Answered by mohapatrakanak28
1

Answer:

age of son= 5 years

after twice year it will be 10 years

it takes five years

so fathers age is 28+5 = 33

Answered by ThanvikaReddie123
0

Answer:after 17 years

Step-by-step explanation:

Present age of son =5 years

Present age of father =28 years

Difference between their ages =23 years

Fathers age =2x

Son's age =x

x+2x=5+28+5

3x=33

x=33/3

x=11

2x=22

But,the present age of father is 28 so,

x=11×2=22

2x=22×2=44

The son's age=22

The father's age =44

There fore, 5+17=22,28+17=44

Hence, after 17 years the father's age will be twice the age of his son

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