The present age of son is five years and his father age is 28 years in how many years will the father's age will be twice the age of his son
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Answered by
1
Answer:
age of son= 5 years
after twice year it will be 10 years
it takes five years
so fathers age is 28+5 = 33
Answered by
0
Answer:after 17 years
Step-by-step explanation:
Present age of son =5 years
Present age of father =28 years
Difference between their ages =23 years
Fathers age =2x
Son's age =x
x+2x=5+28+5
3x=33
x=33/3
x=11
2x=22
But,the present age of father is 28 so,
x=11×2=22
2x=22×2=44
The son's age=22
The father's age =44
There fore, 5+17=22,28+17=44
Hence, after 17 years the father's age will be twice the age of his son
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