Question

The present age of Sumit mother is four times the present age of summit after five years the sum of their ages will be 60 find their present ages

Answer 1

let sumit age be x

mother age = 4x

ratio of sumit : mother (s : m) = 1:4

After five years

given,

sumit age after 5 yrs + mother's age after 5 yrs = 60

=> x+5 + 4x+ 5= 60

=> 5x+ 10= 60

=>x+2 = 12

=> x= 10

so present age of sumit = 10

so present age of sumit mother=4x= 4*10 = 40.

Answer 2

Answer:

the sum of their ages after 5 years is 60. this means that both of their ages is +5 like mothers age is x+5 and summit's age is y+5.to make it present, you have to subtract them by -5 and -5 which is -10 so the sum of their ages in the present is 60-10=50years. mother's age=4 times summit's age which is 4x=x. so 4x+x=50

                             5x=50

         transpose 5 to the RHS

                             x=50/5

                             x=10.

summit's age=x=10 years

mother's age=4x=10*4=40 years