Math, asked by jubliprasad24, 1 month ago

the present age of Sunaina's mother is three times the present age of sunaina. after 5 years their ages will add to 66 years. find present age of sunaina.
please do write useless answer.​

Answers

Answered by Ackshaya12
0

Answer:

susaina s age =14

moms age =42

Step-by-step explanation:

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Answered by CopyThat
8

GIVEN:

  • The present age of Sunaina's mother is three times the present age of Sunaina.
  • After 5 years their ages will add to 66 years.

TO FIND:

  • Present ages of Sunaina and her mother.

SOLUTION:

Let the present age's of Sunaina and her mother be x and 3x years.

After, 5 years their ages will be :

  • x + 5
  • 3x + 5

ATP, sum of their ages is 66 :

  • (x + 5) + (3x + 5) = 66
  • x + 5 + 3x + 5 = 66
  • 4x + 10 = 66
  • 4x = 56
  • x = 56/4
  • x = 14

Hence, the ages are :

  • Sunaina (x) = 14 years.
  • Mother (3x) = 42 years

LEARN MORE:

The Present age of a Man is double the age of his Son. After 8 Years, the ratio of their ages Will Be 7:4. Find the present ages of the Man and his Son.

https://brainly.in/question/42946225

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