The present age of Tanu is 5 years more than Manju 's age. Five years hence now, the age of Tanu will be 15 less than twice of Manju' s age. Find:
1. Their present ages.
2. Their ages three years ago.
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Let the present age of Manju = 'x'.
Given that age of Tanu is 5 years more than Manju's age.
So, the age of Tanu = x + 5 ------ (1)
5 years hence:
= > Age of Manju = x + 5
= > Age of Tanu = x + 5 + 5 = x + 10.
Now,
Given that Age of Tanu will be 15 less than twice of Manju's age.
= > x + 10 = 2(x + 5) - 15
= > x + 10 = 2x + 10 - 15
= > x + 10 = 2x - 5
= > x - 2x = -5 - 10
= > -x = -15
= > x = 15.
(i)
The present age of Manju = 15 years.
The present age of Tanu = 20 years.
(ii)
The age of Manju three years ago = 12 years.
The age of Tanu three years ago = 17 years.
Hope this helps!
Harshi666:
very nice answer
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