The present age of the father and his son is 32 years and 7 years respectively.
Find how many years ago the product of their age was 116.
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Answer:
required answer is 3 years
Step-by-step explanation:
present age father is 32, and his son is 7
x years ago father age=32-x..... equation 1
x years ago his son age is=7-x.....eqn2
product of there ages (32-x)(7-x)=116
224-32x-7x+x^2=116
x^2-39x+108=0
x^2-3x-36x+108=0
x(x-3)-36(x-3)=0
x=3,36
36 years ago means age will be negative
so x=3 years
3 years ago the product of their age is 116
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