Math, asked by kusab, 7 months ago

The present age of the father and his son is 32 years and 7 years respectively.
Find how many years ago the product of their age was 116.​

Answers

Answered by jsanthoshjoshhh
3

Answer:

required answer is 3 years

Step-by-step explanation:

present age father is 32, and his son is 7

x years ago father age=32-x..... equation 1

x years ago his son age is=7-x.....eqn2

product of there ages (32-x)(7-x)=116

224-32x-7x+x^2=116

x^2-39x+108=0

x^2-3x-36x+108=0

x(x-3)-36(x-3)=0

x=3,36

36 years ago means age will be negative

so x=3 years

3 years ago the product of their age is 116

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