Question

the present age of the father is four times that of his son . 20 years hence the age of father will be twice the age of the son . find their present ages​

Answer 1

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the present age of the father is four times that of his son . 20 years hence the age of father will be twice the age of the son . find their present ages

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Age of son = 10 years

Age of father = 40 years

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Let the present age of son be x

Present age of father = 4x

Age after 20 years :-

→ Son's age = x + 20

→ Father's age = 4x + 20

According to the question :-

→ 2( x + 20 ) = 4x + 20

→ 2x + 40 = 4x + 20

→ 4x - 2x = 40 - 20

→ 2x = 20

→ x = 20 / 2

→ x = 10