Question

the present age of the father is four times that of his son . 20 years hence the age of father will be twice the age of the son . find their present ages​

Answer 1

Answer :-

Given :-

Present age of father is four times his son.

After 20 years age of father will be twice the age of son.

To Find :-

Present age of father and son

Solution :-

Let the present age of son be x

Present age of father = 4x

Age after 20 years :-

→ Son's age = x + 20

→ Father's age = 4x + 20

According to the question :-

→ 2( x + 20 ) = 4x + 20

→ 2x + 40 = 4x + 20

→ 4x - 2x = 40 - 20

→ 2x = 20

→ x = 20 / 2

→ x = 10

Age of son = 10 years

Age of father = 40 years

Answer 2

Answer:

let the present age of son be x.

hence.fathers present age=4x

20 yrs hence,

age if son=x+20

father's age=4x+20

4x+20=2(x+20)

4x+20=2x+40

4x-2x=40-20

2x=20

x=10

hence,sons present age is 10 yrs

father's present age us 40 yrss

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