Question

the present age of the father is four times that of his son . 20 years hence the age of father will be twice the age of the son . find their present ages with explanation

Nacho mere dost ki shadi hai
babalagin dhinchak dhinchak hihi​

Answer 1

Answer:

Answer is 40 year

Explanation:

Let the present age of the son = x years

Present age of the father = 4x years

After 20 years,

Son’s age will be (x + 20) years

and Father’s age will be (4x + 20) years

According to the condition,

4x + 20 = 2 (x + 20)4x+20=2(x+20)

4x + 20 = 2x + 40

4x+20=2x+40

4x-2x = 40-20

4x−2x=40−20

2x = 202x=20

⇒x = 20/2⇒x= 20/2

⇒x = 10⇒x=10

∴Present age of the son is 10 years and

Present age of the father is = 4x ×10=40 years.

Answer 2

Question:-

• The present age of the father is four times that of his son . After 20 years the age of father will be twice the age of the son . Find their present age.

To Find:-

• Find the age of father and son.

Solution:-

• Let the present age of son be ' x '

• The father's age is ' 4x '

According to the Question:-

$\longrightarrow\sf \: 4x + 20 = 2( x + 20 )$

$\longrightarrow\sf \: 4x + 20 = 2x + 40$

$\longrightarrow\sf \: 4x - 2x = 40 - 20$

$\longrightarrow\sf \: 2x = 20$

$\longrightarrow\sf \: x = \cancel\dfrac { 20 } { 2 }$

$\longrightarrow\sf \: x = 10$

Hence ,

• Age the son is 10 years.

• Father's age is 4x = 40 years