Math, asked by us358053, 1 month ago

the present age of the father is four times that of his son . 20 years hence the age of father will be twice the age of the son . find their present ages with explanation​

Answers

Answered by BrainlyUnnati
10

QuestioN :

The present age of the father is four times that of his son . 20 years hence the age of father will be twice the age of the son . find their present ages ?

GiveN :

  • Present age of father is four times his son.
  • After 20 years age of father will be twice the age of son.

To FiNd :

  • Present age of father and son

ANswer :

Present age of father is 40 years and son is 10 years.

SolutioN :

Let the present age of son be x

Present age of father = 4x

Age after 20 years :-

→ Son's age = x + 20

→ Father's age = 4x + 20

According to the question :-

→ 2( x + 20 ) = 4x + 20

→ 2x + 40 = 4x + 20

→ 4x - 2x = 40 - 20

→ 2x = 20

→ x = 20 / 2

→ x = 10

∴Present age of father is 40 years and son is 10 years.

________________________________

Answered by misspadhaku01
1

Answer:

We don't talk anymore ---[3 times]

like we used to do

We don't love anymore

Step-by-step explanation:

Similar questions