Question

the present age of the father is four times the age of his son. After 10 years, the age of father will become three times the age of his son. What are their present ages?​

Answer 1

Answer:

Let the present age of son be x.

Present age of father=4x.

Now,

Ten year hence his father age will be 3 times his son.

A/q

\begin{lgathered}4x + 10 = 3(x + 10) \\ 4x + 10 = 3x + 30 \\ 4x - 3x = 30 - 10 \\ x = 20\end{lgathered}

4x+10=3(x+10)

4x+10=3x+30

4x−3x=30−10

x=20

So,

Son age is=20 years

And father age is=4×20=80 years

Answer 2

Step-by-step explanation:

let son's age be x then fathers age will be 4x.

after 10 year son's age will be x+10 then father's age 3( x+10)=4x+10

3x+30=4x+10

30-10=4x-3x

20=x or x=20

present age of son is 20years

father's age is 4 x 20=80