Question

the present age of the father is three times that of his son 5 years ago the sum of their ages is 70 years find their present age​

Answer 1

Answer:

Let

present age of the son be x yrs

then present age of father will be 3x yrs

Step-by-step explanation:

• 5 years ago : age of son :(x-5)yrs and age of father:(3x-5)yrs. By given condition (x-5)+(3x-5)=70 4x-10=70 4x=70+10 4x=80 x=80/4 x=20 Now, present age of son =20 ,also present age father=3x means 3×20=60 Therefore, present age of the son is 20 yrs and that of father is 60 yrs.

Answer 2

SOLUTION:-

Given:

•The present age of the father is 3 times that of his son.

•5 years ago, the sum of their ages is 70 years.

To find:

Their present age.

Explanation:

•Assume the present age of son be R years.

•The present age of father be 3R years.

Five years ago;

The son's age = (R-5) years

The father's age = (3R-5) years.

According to the question:

=) (R-5)+ (3R-5)=70

=) R-5 +3R-5=70

=) 4R-10=70

=) 4R= 70+10

=) 4R= 80

=) R= 80/4

=) R= 20 years

Therefore,

The present age of the son is 20 years.

The present age of the father is 3R years

=) 3×20 years

=) 60 years

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