Question

The present age of the father is twice as old as the age of the son 3 years hence.If 2 years hence the age of the father will be thrice as old as the age of the son 1 year ago. Find their present ages.
Give answer with solution.​

Answer 1

Let son's age = x

Two years ago son's age= x-2.

His Father's age at that time = 3(x-2).

Present age of Father = 3x-6+2=3x-4

Two years hence father's age=3x-4+2=3x-2.

Two years hence son's age = x+2.

Given :-5*(x+2)=2*(3x-2)

5x + 10= 6x - 4

10+4=6x-5x

14=x

SON'S PRESENT AGE : 14 years.

FATHER'S PTESENT AGE: 3

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Answer 2

Step-by-step explanation:

let's sons age = x

tow year ago son's age = x-2

his fathet age at that time =3 (×-2)

present age of father =3×-6 +2 =3×4

tow year hence father's age =3x-4 +2=3x-2

tow year hence son's age =x+2

Give :- 5*(×+2) = 2(3×-2)

5x. + = 10 6×-4

10 + 4 = 6x-5x

14 =x

son's present age : 14

father present age : 3

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