Question

the present age of the father is twice the age of his son. 8 years later,their ages will be in the ratio 7:4.find the age of son

Answer 1

fathers age=48yrs
sons age =24yrs

Answer 2

the present age of father=twice the age of son
let the present age of son =x
therefore the present age of father=2x
8 years later
son age=x+8years
father age=2x+8
A/Q
2x+8/x+8=7/4
4(2x+8)=7(x+8)
8x+32=7x+56
8x-7x+56-32
x=28
therefore present age of son=28 years
and present age of father =2x=56 years