Question

The present age of the son and father are 4 years and 33 years respectively. After how many years the age of the father will be double the age of the son?​

Answer 1

Step-by-step explanation:

Let the son age be, s

Let the father age be, f

Let , after y years father’s age be twice that of the son

2(s+y)=f+y

2(4+y)=33+y

8+2y=33+y

y=25

After 25 years father’s age be twice that of son

Answer 2

Answer:

Present age of son = 4 years.

Present age of father = 33 years.

Let the number of years required be x years.

son's age = (4 + x) years

father's age = (33 + x) years

Here, father's age is twice the age of his son.

$2(4 + x) = (33 + x) \\ 8 + 2x = 33 + x \\ 2x - x = 33 - 8 \\ x = 25$

So, after 25 years, age of father will be twice the age of his son.

Step-by-step explanation:

After 25 years:-

Son's age = (4 + 25) years

= 29 years

Father's age = (33 + 25) years

= 58 years

$29 \times 2 = 58 \\ 58 = 58$

Hence, LHS = RHS