The present age of the son and father are 4 years and 33 years respectively. After how many years the age of the father will be double the age of the son?
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Answered by
9
Present age of the son=4 years
Present age of the father =33 years
Let the years after which the age of the father will be doubled the age of his son be x years
Father age after X years=33+x years
Son age after X years= 4+x years
Father's age is 2 times son's age after X year
So,
33+x= 2(4+x)
=33 + x= 8 + 2x
= (x - 2x) = 8-33
= -x = -25
= x= 25 years
To check,
4+25=29 years
33+25= 58 years
and 58 is double of 29
I hope this answer helps you so please mark this answer as brainliest
Present age of the father =33 years
Let the years after which the age of the father will be doubled the age of his son be x years
Father age after X years=33+x years
Son age after X years= 4+x years
Father's age is 2 times son's age after X year
So,
33+x= 2(4+x)
=33 + x= 8 + 2x
= (x - 2x) = 8-33
= -x = -25
= x= 25 years
To check,
4+25=29 years
33+25= 58 years
and 58 is double of 29
I hope this answer helps you so please mark this answer as brainliest
diksuroa:
I have given the formulae for which you asked.
Answered by
2
Answer: the answer after 25 years
Step-by-step explanation: His son will be 29 and the dad will be 58
29 + 29 = 58
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