Question

the present age of the son is half of the present age of his father. 10 years ago the father was thrice as old as his son. what are there present ages ​

Answer 1

Answer:

present age of father = 40

present age of son = 20

Step-by-step explanation:

let the present age of father be x

son's present age will be 1/2 x

ten years ago

age of father = x - 10

age of son = 1/2 x - 10

ten years ago father's age was thrice of son's age

x - 10 = 3(1/2x - 10)

\begin{lgathered}x - 10 = \frac{3}{2} x - 30 \\ \frac{3}{2} x - x = - 10 + 30 \\ \frac{3x - 2x}{2} = 20 \\ \frac{x}{2} = 20 \\ x = 20 \times 2 \\ x = 40\end{lgathered}x−10=23x−3023x−x=−10+3023x−2x=202x=20x=20×2x=40

present age of father = x = 40

present age of son = 1/2 x = 1/2 × 40 = 20

hope you get your answer

Answer 2

Answer:

10 years

Step-by-step explanation:

The age of father 10 years ago was thrice the age of his son. 10 years hence father's age will be twice that of his son