Question

The present age of three persons are in proportions 4:7:9. Eight years ago, the sum of their ages was 56. Find their present ages?

Answer 1

Answer:

Person 1 = 16 , Person 2 = 28 , Person 3 = 36

Step-by-step explanation:

Let age of person 1 be= 4x

Let age of person 2 be= 7x

Let age of person 3 be= 9x

Their age 8 years ago :

Person 1: 4x-8

Person 2: 7x-8

Person 3: 9x-8

Sum of their ages 8 years ago: 56

4x-8+7x-8+9x-8=56

20x- 24 =56

20x= 56+24

x = 80/20

x = 4

Therefore, ages of

Person 1 = 4*4= 16

Person 2 =7*4= 28

Person 3 =9*4= 36