Question

The present age of two brother
are in Ratio 3:4 five
their ages were in the Roto of
5:7 find their present age.
year back​

Answer 1

${ \pink{ \underline{ \underline{ \sf \purple{ GIVEN : }}}}}$

• The ratio of their present age is 3:4 years.
• Five years ago their ratio was 5:7 years.

${ \pink{ \underline{ \underline{ \sf \purple{ TO \: FIND : }}}}}$

• Their present age.

${ \pink{ \underline{ \underline{ \sf \purple{SOLUTION : }}}}}$

• Let their ages be 3x and 4x years respectively.

NOW,

Five years ago :

(3x - 5) and (4x - 5) years.

THEREAFTER,

according to the question,

$\sf \implies \frac{(3x - 5)}{(4x - 5)} = \frac{5}{7}$

$\sf \implies \: 7(3x - 5) = 5(4x - 5)$

$\sf \implies \: 21x - 35 = 20x - 25$

$\sf \implies \: 21x - 20x = 35 - 25$

$\bf \therefore \: x = 10$

HENCE,

Their present age is :

3x = 3 × 10 = 30 years.

4x = 4 × 10 = 40 years.

Answer 2

Answer:

5(4x-5) = 7(3x-5)

20x - 25 = 21x - 35

x = 10

present ages = 30,40

Step-by-step explanation:

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