Question

The present age of two children Shikhar and John are in the ratio 5 :8. Four years later the sum of their ages will be 34 years. Find the present ages.

Please solve in book and send ​

Answer 1

Answer:

Shikhar's age = 10 years

John's age = 16 years

Step-by-step explanation:

Shikhar's age = x

John's age = y

∴Four years later

Shikhar's age = x+4

John's age = y+4

$\dfrac{x}{y}=\dfrac{5}{8}$

$\begin{aligned}(x+4)+(y+4)&=34\\x+y+8&=34\\x+y&=34-8\\x+y&=26\end{aligned}$

Question :

Find the present ages!

Solution :

$\begin{aligned}x+y&=26\\x&=26-y\end{aligned}$

• Find the John's age (y)

$\begin{aligned}\dfrac{x}{y}&=\dfrac{5}{8}\\\dfrac{26-y}{y}&=\dfrac{5}{8}\\8(26-y)&=5y\\208-8y&=5y\\8y+5y&=208\\13y&=208\\y&=16~\rm{years}\end{aligned}$

So, the John's age is 16 years.

• Find the Shikhar's age (x)

$\begin{aligned}x&=26-y\\&=26-16\\&=10~\rm{years}\end{aligned}$

So, the Shikhar's age is 10 years.

I hope this helps you

Correct me if I'm wrong, thanks