the present age of wife and husband is 52 and 58 what if at the time of their marriage the ratio is 13 and 16.
Answers
Answered by
2
Answer:
Let present age of the man and his wife be
4
x
and
3
x
respectively.
After
4
years this ratio will become
9
:
7
⇒
(
4
x
+
4
)
:
(
3
x
+
4
)
=
9
:
7
⇒
7
(
4
x
+
4
)
=
9
(
3
x
+
4
)
⇒
28
x
+
28
=
27
x
+
36
⇒
x
=
8
Present age of the man
=
4
x
=
4
×
8
=
32
Present age of his wife
=
3
x
=
3
×
8
=
24
Assume that they got married before
t
years. Then,
(
32
−
t
)
:
(
24
−
t
)
=
5
:
3
⇒
3
(
32
−
t
)
=
5
(
24
−
t
)
⇒
96
−
3
t
=
120
−
5
t
⇒
2
t
=
24
⇒
t
=
24
2
=
12
Answered by
2
Answer:
26 and 32
Step-by-step explanation:
Present Age of Wife and Husband is 52 and 58. Thus a difference of 6 years.
Now, as per ratio 13:16 the difference here is only 3.
So we divide the age of Wife by 2, therefore 52/2=26 years
Now husband is 6 years older,
So, husband's age is 26+6= 32 years
Hope it helps. Otherwise you can use longer method.
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