Math, asked by KristiPhukan, 17 days ago

The present age of x is five times of the age of his son. After four years, the age of x will be four times the age of his son. Find the present age of his son.​

Answers

Answered by jaideepan2009
0

Answer:

Let the age of son be x.

Thus, age of father is 4x.

After 5 years, their ages will be x+5 and 4x+5 years respectively.

As per the question, we have

4x+5=3(x+5)

⇒4x+5=3x+15

⇒x=10

Age of father will be 4x=4×10=40 years.

Thus when son is 10 years old, father is 40 years.

THANK YOU

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