Question

the present age pf a and b are in the ratio 7:5 and 10 years later their age will be in the ratio 9:7 find the present age please upload in pen paper form or in full method
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Answer 1

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Answer 2

Given:

• Present age of A and B are in the ratio 7:5.
• 10 years later their age will be in the ratio 9:7.

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To find:

• Present age of a and b?

⠀━━━━━━━━━━━━━━━━━━━━━━━━

☯ Let's consider the present age of A and B be 7x and 5x respectively.

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$\underline{\bigstar\:\boldsymbol{According\:to\:the\:question\::}}$

• 10 years later their age will be in the ratio 9:7.

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Their ages after 10 years,

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• Age of a = (7x + 10) years
• Age of b = (5x + 10) years

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Therefore,

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$:\implies\sf \dfrac{7x + 10}{5x + 10} = \dfrac{9}{7}$

$:\implies\sf 7(7x + 10) = 9(5x + 10)$

$:\implies\sf 49x + 70 = 45x + 90$

$:\implies\sf 49x - 45x = 90 - 70$

$:\implies\sf 4x = 20$

$:\implies\sf x = \cancel{ \dfrac{20}{4}}$

$:\implies{\underline{\boxed{\frak{\purple{x = 5}}}}}\;\bigstar$

Hence,

• Present age of A, 7x = 7 × 5 = 35 years
• Present age of B, 5x = 5 × 5 = 25 years