the present ages of a and b are in ratio 7:5 ten years later their ages will be in ratio 9:7 find their present ages plz explain with clear steps
Answers
Answered by
1
Answer:
let A's age be 7x
B's age be 5x
Ten Years Later
A's age = 7x + 10 = 9x (given)
Bs age = 5x + 10 = 7x
7x 10 = 9x
10 = 9x - 7x
10 = 2x
x = 10÷2
x = 5
A's present age = 7x =7 ×5 = 35
Bs present age = 5x = 5 × 5= 25
Answered by
1
Answer:
Their present ages are 35 and 25
Step-by-step explanation:
Let 7x and 5x be their present ages.
Given,
After 10 years their ages will be 9x and 7x.
Therefore,
7x+10=9x(i)
5x+10=7x(ii)
Taking (i),
7x+10=9x
=> 9x-7x=10
=> 2x=10
=> x=5
Therefore the value of x is 5.
Therefore replacing x by 5 in the present ages we get,
7x=7*5=35
5x=5*5=25
Therefore their present ages are 35 and 25.
[We need not use (ii) unless there are two variables]
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