Math, asked by mjbishu, 1 year ago

the present ages of A and B are in ratio 7:5 . ten years later ages will be in ratio 9:7 . find their present ages? (linear equation)

Answers

Answered by Parth2005
1
Let their present ages be A - 7x B - 5x


After 10 years

A - 7x + 10 or 9x

B - 5x + 10 or 7x

Then

7x + 10 = 9x
10 = 9x - 7x
10 = 2x
x = 10/2
x = 5


Present age
A = 5*7 = 35
B = 5*5 = 25
Answered by Battleangel
3

refer to the attachment ✌

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