Math, asked by palakgupta2395, 4 months ago

The present ages of A and B are in the ratio 4:5. Ten years ago, their ages were in ratio 3:4. What are their present ages?​

Answers

Answered by archana04087438
1

Answer:

Let the age of A and B are 4x and 5x

According to question,

ten years ago ,

5x−10

4x−10

=

4

3

(4x−10)4=(5x−10)3

16x−40=15x−30

x=10

So their present ages are 4(10)=40 , 5(10)=50.

Answered by Anonymous
5

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