The present ages of A and B are in the ratio 5 : 6. Three years ago, their ages were in the ratio 4 : 5. Find their present ages
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Answer:
- A = 15
- B = 18
Step-by-step explanation:
Given:
- Present ages of A and B are in ratio of 5 :6.
- Three years ago their ages were in ratio 4 : 5.
To Find:
- What are their ages ?
Solution:
- Let x be the common in given ratios.
∴ ,
- A's age = 5x years
- B's age = 6x years
[ Now, three years ago their ages were ]
- A's age = (5x – 3) years
- B's age = (6x – 3) years
A/q
Three years ago their ages were in ratio 4 : 5.
(5x – 3) : (6x – 3) = 4 : 5
(5x – 3)/(6x – 3) = 4/5
5(5x – 3) = 4(6x – 3)
25x – 15 = 24x – 12
25x – 24x = – 12 + 15
x = 3
So, present ages of
- A = 5x = 5(3) = 15 years
- B = 6x = 6(3) = 18 years
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