Math, asked by rainbowfairy, 5 months ago

The present ages of A and B are in the ratio 5 : 6. Three years ago, their ages were in the ratio 4 : 5. Find their present ages​

Answers

Answered by ashauthiras
7

Answer:

  • A = 15
  • B = 18

Step-by-step explanation:

Given:

  • Present ages of A and B are in ratio of 5 :6.
  • Three years ago their ages were in ratio 4 : 5.

To Find:

  • What are their ages ?

Solution:

  • Let x be the common in given ratios.

∴ ,

  • A's age = 5x years
  • B's age = 6x years

[ Now, three years ago their ages were ]

  • A's age = (5x – 3) years  
  • B's age = (6x – 3) years

A/q

Three years ago their ages were in ratio 4 : 5.

(5x – 3) : (6x – 3) = 4 : 5

(5x – 3)/(6x – 3) = 4/5

5(5x – 3) = 4(6x – 3)

25x – 15 = 24x – 12

25x – 24x = – 12 + 15

x = 3

So, present ages of

  •  A = 5x = 5(3) = 15 years
  • B = 6x = 6(3) = 18 years
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