Question

the present ages of A and B are in the ratio 7:5. ten year later, their ages will be in the ratio 9:7. find their present ages.
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Answer 1

Step-by-step explanation:

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Answer 2

$\huge \blue\star \: \pink{ \underline { \textbf{\textsf{Solution :- }}}}$

Let the present age of A = 7x years

The present age Of B = 5x years

After 10 years, their ages will be

A = 7x + 10 years

B = 5x + 10 years

The ratio of the ages after 10 years 9 : 7

$\implies\large \frac{7x + 10}{5x + 10} = \frac{9}{7}$

${\implies49x + 70 = 5x + 90}$

${\implies49x - 45x = 90 - 70}$

${\implies4x = 20}$

${\implies x = 5}$

Present age of A = 7 × 5 = 35 Years

Present Age of B = 5 × 5 = 25 Years