Question

The present ages of A and B are in the ratio 7 : 5. Ten years later, their ages will
be in the ratio 9:7. Find their present ages. @*PLEASE HELP*@​

Answer 1

Answer:

Let A be Leena and B be Heena.

So,

Let the rational between ages of Leena and Heena be x.

The ages of Leena and Heena are in the ratio 7:5.

Thus there ages are, Leena 7x and Heena 5x

Ten years hence, the ratio of their ages will be 9:7.

10 year hence their ages will be:

Leena’s age 7x + 10

Heena’s age 5x + 10

The ratio of their ages

7x + 10 / 5x + 10 = 9 / 7

Cross multiplication:

9 ( 5x + 10 ) = 7 ( 7x + 10 )

45x + 90 = 49x + 70

45x - 49x = 70 - 90

—5x = -20

5x = 20

x = 20/5

x = 4

The rational is 4

Their respective ages are,

Leena’s age 7x = 7 × 4 = 28 years

Heena’s age 5x = 5 × 4 = 20 years

•°• Leena’s age is 28 years and Heena’s age is 20 years.

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Answer 2

Answer:

35 and 25 respectively

Step-by-step explanation:

let the present age of a and b be 7x and 5x respectively

acc to ques

10+7x=9x → 10=2x →x=5

also , 10+5x= 7x →10=2x→ x=5

hence x=5

now putting the value of x

a's age = 7x=7×5=35

B's age = 5x=5×5=25

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