Question

The present ages of A and B are in the ratio 7:5. Ten years later, their ages will
be in the ratio 9: 7. Find their present ages.​

Answer 1

Answer:

equally important is broking

Answer 2

$\therefore\textbf{Let the current ages of Leena and Heena be x and y respectively}$

$\boxed{\bf{Ratio\: is\: 7:5\: x:y\: is\: 7:5}}$

$\sf x/y =7/5$

$\sf 5x=7y$

$\sf 5x-7y=0$ --i

After 10 yrs

The ratio is 9:7

$\sf (x+10)/(y+10) =9/7$

$\sf 7x+70=9y +90$

Solving the above equation.

$\sf 7x-9y=20$ —ii

Solve eq-i &eq-ii on both side.

$\sf 7x-9y=20$

$\sf 5x-7y=0$

$\sf x=7y/5$

substitute the value of X in eq-ii

$\sf 7*7y/5–9y=20$

$\sf 49y-45y=100$

$\sf 4y=100$

$\sf y=25$

$\sf x =7*25/5 = 35$

$\mapsto\bf{Leena\: is\: 35yrs}$

$\mapsto\bf{Heena\: is\: 25yrs.}$