the present ages of a and bare in the ratio 7:5.ten years later there ages willbe in the ratio 9:7.find the present ages
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Let the present age of a = x,
Let present age of b = y,
After ten years,
Their ages will be (x+10) and (y+10) respectively,
Now according to the data,
x/y = 7/5, Cross multiply,
=> 5x = 7y,
=> x = 7y/5
and also,
(x+10) / (y+10) = 9/7, Cross multiply,
=> 7x + 70 = 9y + 90
Substitute x here,
=> 49y /5 + 70 = 9y + 90,
=> 49y + 350 = 45y + 450,
=> 4y = 100,
=> y = 25,
=> x = 7*25/5 ,
=> x = 35,
Therefore present age of a = 35 yrs, and present age of b = 25 yrs,
Hope you understand,
Have a great day !!
Let present age of b = y,
After ten years,
Their ages will be (x+10) and (y+10) respectively,
Now according to the data,
x/y = 7/5, Cross multiply,
=> 5x = 7y,
=> x = 7y/5
and also,
(x+10) / (y+10) = 9/7, Cross multiply,
=> 7x + 70 = 9y + 90
Substitute x here,
=> 49y /5 + 70 = 9y + 90,
=> 49y + 350 = 45y + 450,
=> 4y = 100,
=> y = 25,
=> x = 7*25/5 ,
=> x = 35,
Therefore present age of a = 35 yrs, and present age of b = 25 yrs,
Hope you understand,
Have a great day !!
variable1:
thank you very much
Answered by
2
by solving eqn 1 and 2 we get x as 5 and y as 5 so their ages are 35 and 25
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