Question

The present ages of A,B and C are in proportions 4:7:9. Eight years ago, the sum
of their ages was 56. What are their present ages (in years)? *
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Answer 1

Answer:

Let their present ages be 4x, 7x and 9x years respectively.

Then, (4x - 8) + (7x - 8) + (9x - 8) = 56$$

⇒20x=80

⇒x=4

∴ Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years respectively