Math, asked by gurralanarendra5, 5 months ago

The present ages of A, B and C are in the
ratio 2:3:5. The sum of their ages after
5 years will be 85 years. Find the age of C
8 years ago?
[ ]


what is the answer??​

Answers

Answered by ladnomamit1992
2

Answer:

answer is 32

Step-by-step explanation:

5×3=15 which will be subtracted from 85 the will get 85-15=70 then we have to add 2+3+5=10 then we have to divide 70 by 10=7 then 7×5=35 then 35 -3 =32

Answered by kaumudi61
4

Answer:

your ans is as follows

Step-by-step explanation:

the ratio is 2:3:5

Hence, let the ages of a b and c be 2x 3x and 5x resp.

Hence their ages after 5 years will be (2x + 5), (3x + 5) and 5x + 5) resp.

according to the condition,

2x + 5 + 3x + 5 + 5x + 5 = 85

10x + 15 = 85

10x = 70

x = 7

Hence, present age of c = 5x = 7×5 = 35

age of c 8 years ago = 35 - 8 = 27

Hence age of c 8 years ago is 27 years

HOPE THIS HEPLS YOU

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