Question

The present ages of a father and his daughter is x years and y years respectively.Three years hence father will be three times as old as his daughter 7years ago he was seven times as old as his daughter find this present ages

Answer 1

Answer:

father is 42 and daughter is 12 years old

Step-by-step explanation:

let father age be x years

daughter age be y years

3 years hence,father will be 3 times old as his daughter.

therefore,father's age becomes (x+3) and daughter age becomes 3(y+3).

(x+3)=3(y+3)

x+3=3y+9

x-3y-6=0 ....(1)

7 years ago,father is 7 times old as his daughter.

therefore, father age becomes (x-7) and his daughter age becomes 7(y-7).

(x-7)=7(y-7)

x-7=7y-49

x-7y+42=0...(2)

x-3y-6=0

x-7y+42=0

(-) (+) (-)

=4y-48=0

4y=48

y=48/4

y=12

put y=12 in equation (1)

x-3(12)-6=0

x-36-6=0

x-42=0

x=42

therefore, father age x years=42 years

daughter age y years=12 years

Answer 2

Answer:X=27 and Y=7

Step-by-step explanation: