Math, asked by sushmitakhadgi89, 11 months ago

the present ages of a father and his son are 40 years and 8 years respectively how many years ago the product of their ages was 105​

Answers

Answered by scifikb507
7

Answer:

21 and 5 because 21×5=105.

Answered by AbhigyaDestiny
3

Answer:

5 years

Step-by-step explanation:

x years ago, the product of their ages was 105,

(40-x)(8-x) = 105

320-40x-8x+x^2 = 105

x^2-48x+215=0

x^2-48x+43*5=0

(x-43)(x-5)=0

Either,

x-5=0

x = 5 years

OR

x-43=0

x=43 years [rejected,x<8]

So, 5 years ago, the product of the father and son’s ages was 105.

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