the present ages of a father and his son are 40 years and 8 years respectively how many years ago the product of their ages was 105
Answers
Answered by
7
Answer:
21 and 5 because 21×5=105.
Answered by
3
Answer:
5 years
Step-by-step explanation:
x years ago, the product of their ages was 105,
(40-x)(8-x) = 105
320-40x-8x+x^2 = 105
x^2-48x+215=0
x^2-48x+43*5=0
(x-43)(x-5)=0
Either,
x-5=0
x = 5 years
OR
x-43=0
x=43 years [rejected,x<8]
So, 5 years ago, the product of the father and son’s ages was 105.
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