Math, asked by himansu4064, 1 year ago

The present ages of ankitha and sunitha are in the ratio of 6:7. 6 years hense this ratio will become 7:8 respectively.What is ankitha's present age

Answers

Answered by Anonymous
63

◀ HEY THERE! ◀




◀ Question: ◀



The present ages of Ankita and Sunita are in the ratio is 6:7.  6 years hence this ratio will become 7:8 respectively.  What is Ankita’s present age in years?


◀  Method of Solution: ◀



→ Let their Present age will be x,



→ Present ages of Ankita and Sunita are in the ratio is 6:7.



⇒ 6x/7x



→ According to the Question's Statement!



⇒ 6x+6/7x+6 = 7/8



⇒ 8(6x+6)=7(7x+6)



⇒ 48x+48=49x+42



⇒ 48x-49x = 42-48



⇒ -x = -6



•°• x = 6



Then, → Present Age of Ankitha's = 6x



•°• Present age of Ankitha's = 36 Years


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Answered by Awesome98
24
A/Q,


6x+6/7x+6 = 7/8

8{6x+6)}=7{7x+6}

48x+48=49x+42

48x-49x = 42-48

x = 6



Present age of Ankitha's = 36 Years
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