Question

The present ages of daughter and father are in the ratio 1:6. After 5 years the ratio of their ages will be 2:7. What is the present age of the son who is 2 years younger than the daughter?​

Answer 1

Answer:

his age will be 19

Step-by-step explanation:

befite his father age he is the in ratio of

Answer 2

⤀ Given :

• The present age of daughter and father are in the ratio 1:6
• After 5 years the ratio of their ages will be 2:7

⤀ To Find :

• What is the present age of the son.
• Who is 2 years younger than the daughter.

⤀ Let Us Assume :

$\huge\blue \star \sf \large \underline \red{ \: The \: Present \: Ages \: of}$

• $\tt \pink{Daughter = x}$
• $\tt \pink{Father = y}$
• $\tt \pink{Son = z}$

$\huge\green \star \sf \large \underline \purple{ \: Present \: Ages \: of \: Daughter \: and \: Father}$

• $\sf \large \red \implies \blue{x:y = 1:6}$
• $\sf \large \red \implies \blue{ \frac{x}{y} = \frac{1}{6} }$
• $\sf \large \red \implies \blue{6x = y}$

$\huge\red \star \sf \large \underline \green{ \: After \: 5 \: Years \:}$

$\sf \red \implies \blue{(x + 5):(y + 5) = 2:7}$

$\huge\purple \star \sf \small \underline \pink{ \: Substituting \: The \: Value \: of \: y }$

$\sf \red \implies \blue{x + 5) = (6x + 5) = 2:7}$

$\sf \red \implies \blue{ \frac{(x + 5)}{(6x + 5)}} \sf \blue {= \frac{2}{7}}$

$\sf \red \implies \blue{7(x + 5) = 2(6x + 5)}$

$\sf \red \implies \blue{7x + 35 = 12x + 10}$

$\sf \red \implies \blue{35 - 10 = 12x - 7x}$

$\sf \red \implies \blue{25 = 5x}$

$\sf \red \implies \blue{ \frac{25}{5} = x = 5}$

$\huge\blue \star \sf \small \underline \red{ \:The \: Present \: Age \: of \: The \: Son }$

$\sf \red \implies \blue{z = x - 2}$

$\huge\purple \star \sf \large \underline \pink{ \:Putting \: The \: Value \: of \: x }$

$\sf\red \implies \blue{z = 5 - 2}$

$\sf \red \implies \blue{z = 3}$

• Hence the present age of the son is 3 years.