Question

The present ages of daughter and father are in the ratio 1:6. After 5 years the ratio of their ages will be 2:7. What is the present age of the son who is 2 years younger than the daughter?​

Answer 1

Given that:

• The present ages of daughter and father are in the ratio 1 : 6.
• After 5 years the ratio of their ages will be 2 : 7.

To Find:

• What is the present age of the son who is 2 years younger than the daughter?

Let us assume:

The present ages of:

• Daughter = x
• Father = y
• Son = z

Present ages of daughter and father,

↠ x : y = 1 : 6

↠ x / y = 1 / 6

↠ 6x = y

After 5 years,

↠ (x + 5) : (y + 5) = 2 : 7

Substituting the value of y.

↠ (x + 5) : (6x + 5) = 2 : 7

↠ (x + 5) / (6x + 5) = 2 / 7

↠ 7(x + 5) = 2(6x + 5)

↠ 7x + 35 = 12x + 10

↠ 35 - 10 = 12x - 7x

↠ 25 = 5x

↠ 25/5 = x = 5

The present age of the son,

↠ z = x - 2

Putting the value of x.

↠ z = 5 - 2

↠ z = 3

Hence,

• The present age of the son is 3 years.

Answer 2

Answer:

Step-by-step explanation:

given :

• age of daughter and father = 1:6

• ratio of their ages = 2: 7

to find :

• present age of the son = ?

• present age of the son = ?

solution :

• Let the present age of father and son be F and S. Therefore,

• F/S = 1/6

• F = 1 s

• and after 5 years

• (Father+ 5)/(Son+5) = 2/7

• 7 Father + 10 = 2 Son + 35

• 7 Son + 35 = 12 Son + 10

• 35 Son - 10 = 12 Son - 7

• 25 Son = 5

• Son = 5

• then we will minus

• 5 Sons - 2 sons

• = 3 sons

thus, the answer is 3 sons