Question

. The present ages of daughter and father are in the ratio 1:6. After 5 years the ratio of
their ages will be 2:7. What is the present age of the son who is 2 years younger than the
daughter?

Answer 1

Answer:

present age of son is 3 years.

Step-by-step explanation:

let the ratio of daughter and father be 1k and 6k respectively.

after 5 years

daughters age will be k + 5

father's age will be 6k + 5

$\frac{k + 5}{6k + 5} = \frac{2}{7 }$

7k + 35 = 12k + 10

35-10=12k-7k

25= 5k

5=k

daughter's age = 5years

son's age = 5-2 = 3 years.

Mark it as brainliest!!

Answer 2

Answer:

3

Step-by-step explanation:

Let present age of daughter be x and father be 6x.

After 5 years :

x + 5 / 6x + 5 =2 /7

7(x+5) =2(6x +5)

7x + 35 = 12x + 10

x = 5

Hence present age of daughter is 5 and father is (6*5) = 30

And present age of son will be (5-2) = 3