Math, asked by paramitakar145, 6 months ago

the present ages of derek and saniya are in the ratio 3:4.Five years from now the ratio of their ages will be 4:5.Find their present ages?​

Answers

Answered by jeetmit4
0

Answer:

Derek=15, Saniya=20

Step-by-step explanation:

let, Derek's current age be 3x

and, Saniya's current age be 4x

or, given that

3x+5:4x+5= 4:5\\\\or, \frac{3x+5}{4x+5}=\frac{4}{5}\\or, 5(3x+5)=4(4x+5)\\or, 15x+25= 16x+20 \\or, 25-20= 16x-15x\\or, x=5

thus, Derek's present age is 3x=3×5 = 15

similarly, Saniya's present age is 4x=4×5= 20

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